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Q: Tanvir runs and walks 10 km from her home to school and then back again each day. She runs for the first 8 km at the speed of 15 km per hour she walks the last 2 km at the speed of 6 km per hour?
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The last moment, the speed is the final, the first moment, the speed is zero, average=final /2. For the bit just before the final, and the bit an equal bit just after the start the average is again final/2. For every instant before the final, coupled with the same instant after the start, the average is final/2. So the average for the whole trip is final/2. So to get the final, multiply the average by 2.


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Well, speed is equal to distance over time (s = d/t) However, velocity means speed WITH direction. This means that the teacher's drive to school would be a positive velocity, but the drive back would be a negative one. Now, let's calculate velocities using the s = d/t formula! Distance to school from home: speed = distance/time speed = +10 miles/20 minutes speed = 1/2 miles per minute Distance from school to home: speed = distance/time speed = -10miles/20 minutes speed = -1/3 miles per minute Note: the velocity towards home will be negative since we are travelling in the opposite direction of the distance to school (which is positive) We have our two velocities- let's calculate the average! 1/2 -1/3 = 1/6 1/6 divided by 2 = 1/12 Thus, our average velocity is 1/12 miles per minute! You can convert this into decimal values if required. Hope this helped! (:

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