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If you choose one person, then consider your options for a second, you have nine people for them to play against. Then, considering the second person, excluding the match already played with the first person, you have eight possible matches. Following this all the way, the number of unique matches are:

9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 45

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Q: Ten students are playing in a chess tournament If each student plays every other student once how many total games are played?
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