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Q: The area of a rhombus equals one-half times the product of the lengths of its diagonals?
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The area of a rhombus equals two times the product of the lengths of its diagonals?

false


Area of rhombus?

Half the product of the lengths of its diagonals. A=1/2(d1*d2)


How do you find the measures of a rhombus with two diagonals?

That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.


If the diagonals of the rhombus are in the ratio 3 to 4 and the perimeter of the rhombus is 40 cm what are the lengths of the diagonals?

The lengths of the diagonals work out as 12 cm and 16 cm


Are diagonals of a rhombus parallel?

noNo, the diagonals of a rhombus are perpendicular to each other.Unless the rhombus is regular (and called a square) the diagonals are of different lengths.


What is the area of rhombus ABCD if AC 7 and BD 12?

The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.


If the lengths of the diagonals of a rhombus are 6 and 8 what is the perimeter of the rhombus?

the answer is 20


What is the area of a rhombus if ac equals 14 bd equals 17 and ab equals 11?

The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonalsIn your case, that's 14 x 17 / 2 = 119


Why do the diagonals of a rhombus not have to be the same length?

The sides of a rhombus must all be the same length, but the angles do not need to be the same. The result is a diamond shape where the diagonals can be two different lengths.


The area of a rhombus equals one-half times the sum of the lengths of its diagonals?

false


Which four-sided shape has all sides equal and diagonals that are different lengths?

It is a rhombus


How do you find the measure of the sides of a rhombus by its diagonals?

The diagonals of a rhombus bisect one another at right angles. So you can use Pythagoras on half the lengths of the diagonals. If the two diagonals ore of lengths a and b, then side2 = (a/2)2 + (b/2)2 or, equivalently, side = 1/2*sqrt(a2 + b2)