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Q: The difference between two 3 digit numbers is a palindrome between 200 and 300. what are the numbers?

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999-101=898

There are 800 such numbers.

There are 17 such numbers.

Answer1 x 9 (number of 1 digit numbers) plus 2 x 89 (number of 2 digit numbers) plus 3(number of 3 digit numbers) x 347 = 1228 The correct answer is 1323. Here is how you do it.1 digit numbers = 92 digit numbers = 90 (99-9) number of 2 digit numbers - number of 1 digit numbers3 digit numbers = 378 (477-99) number of 3 digit numbers - number of 1 & 2 digit numbersSo, the solution is:1x9 = 92x90 = 1803x378 = 11349+180+378 = 1323

An irrational number is expressed as a non-repeating decimal that goes on forever. Write out the enough of the decimal expansion of each number to find the first digit where the two numbers disagree. Truncate the larger number at that digit, and the result is a rational number (terminating decimal) that is between the two.

Related questions

-1

There is no limit to numbers, thus there is no limit to palindrome numbers.

9999

95

9888

1, 2, 3

There is no difference. In both cases, the place value, of any digit, is ten times the place value of the digit to its right.

86

As the numbers are between 200 and 300 then the first and last digits must be 2 ; the numbers must be 2?2. The possible palindromic numbers in this range are 202, 212, 222, 232, 242, 252, 262, 272, 282 and 292. The difference between any two of these numbers is a number between 10 and 90 which is a multiple of 10.

Any, and every, number can be transformed into a palindrome.

The largest 5-digit number is 99,999, the smallest is .00001,and the difference is 99,998.99999 .If you only want to consider whole numbers, then the smallest is 10,000and the difference is 89,999 .

There can only be one largest two-digit prime number.

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