No. The distance to the Moon and back is 500,000 miles, which would take 10 days (500,000 divided by 50,000), which is more than a week (7 days).
Or, to put it another way, the trip there takes 250,000 miles/ 50,000 miles a day = 5 days, so for the week you would only have 2 days left (7-5) and it takes 5 days, at the same speed, to get back.
No, it is not possible to determine the speed of someone in space based on the information given. To calculate speed, we need to know the distance traveled and the time it took to travel that distance, and in this case, we don't have either of those values. We know that one year on the spaceship is equal to 50000 years on Earth, but that does not provide us with any information about the speed of the spaceship.
Since 1 AU is the distance from the Sun to the Earth and it takes about 8 Minutes for light to travel such a distance this problem can be solved by simple multiplication and division.(50,000 AU)(8 Minutes)=400,000 Minutes/60 (Minutes/Hour)=6666.67 Hours/24 (Hours/Earth Day)=277.78 DaysSo the answer is 277.78 Earth Days or 0.76 Earth Years!
The sphere far outside the Solar System is called the "Oort Cloud", after the astronomer who predicted its existence.
$50000
2083.333 days.
The Number of TopoSheets of 50000 scale fall in to 250000 scale will be 16. Please tell me what would be the distance in KM in One Degree of 250000 scale toposheet
No, it is not possible to determine the speed of someone in space based on the information given. To calculate speed, we need to know the distance traveled and the time it took to travel that distance, and in this case, we don't have either of those values. We know that one year on the spaceship is equal to 50000 years on Earth, but that does not provide us with any information about the speed of the spaceship.
0.2 * 250000 = 50000
0.2
500000
50,000
Anywhere between 50000-250000 depending on what they fly and where.
25000
46000 is nearer to 50000 than it is to 40000. So, to the nearest ten thousand 246000 becomes 250000.
50000 km
50000 miles
The distance is about 786 air miles.