Numbers are a, b and c; b = a + 2, c = a + 4.
Find a such that a = b + c, ie a = (a + 2) + (a + 4)
so a = 2a + 6 making a = -6, b = -4 and c = -2
Integers are whole numbers therefore it follows that two consecutive integers can't result into a decimal number
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
hi
There are an infinite number of prime numbers which are consecutive odd integers. Choose any natural number n. Take all primes up to any number n, take their product, and add 1 and subtract 1 from it. These 2 numbers are consecutive odd integers. eg 2*3*5*7 = 210 209 and 211 are primes which are consecutive odd integers.
Consecutive numbers implies integers. Rational or real numbers are infinitely dense so there is no "next" number. There can be no pairs of integers such that their product is a fractional number between 559 and 560.
Integers are whole numbers therefore it follows that two consecutive integers can't result into a decimal number
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
hi
Consecutive integers are integers that follow in sequence. Each number is 1 more than the previous numbers.
There are an infinite number of prime numbers which are consecutive odd integers. Choose any natural number n. Take all primes up to any number n, take their product, and add 1 and subtract 1 from it. These 2 numbers are consecutive odd integers. eg 2*3*5*7 = 210 209 and 211 are primes which are consecutive odd integers.
Consecutive numbers implies integers. Rational or real numbers are infinitely dense so there is no "next" number. There can be no pairs of integers such that their product is a fractional number between 559 and 560.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
L = 22 - x. There is no solution in integers for this statement: it is not possible in this Universe for two consecutive numbers to add to an even number. Nearest answer is 10½ and 11½.
There is no such thing as consecutive numbers because numbers are infinitely dense. Between any two numbers there is another and so there is no such thing as a "next" number.There are no integers (square or non-square) between any two consecutive integers. There are infinitely many numbers between any two consecutive integers and, if the integers are non-negative, every one of these will be a square of some number so the answer is none. If the integers are negative then the infinitely many numbers will have a square root in the complex field but not in real numbers. In this case the answer is either none or infinitely many, depending on the domain.
None exist. 100 is an even number and two consecutive integers can only add up to an odd number. This is because only 2 evens can add up to an even number and no two even numbers are consecutive. (or two odds, but no two odd numbers are consecutive either)
It's an imaginary number, one that exists only in fiction, if the author wants it to. There are no two consecutive integers whose sum is 66. 32 + 33 = 65 33 + 34 = 67 The sum of two consecutive integers is always an odd number.
There are no such numbers. If S is the sum of any 4 consecutive integers then S = 2 (mod 4) In other words, any four consecutive integers add up to an even number that is NOT dvisible by 4.