In order to calculate the volume of a rectangular wet wall, one would first measure the wall's length, width, and depth. Then, one would plug the measurements into this formula: length x width x height.
well, that depends. assuming that the liquid is filling the rectangle, and that the rectangle is not flat on paper or anything, it would be Base * Width * Height
The mass will decrease as well. There is a formula for calculating said change, M(mass) = D(density) x V(volume).So if the volume were to remain constant and the density were to decrease, then the result would be smaller, as I previously stated above.
well, they can, but they dont have to be no. :)
well this is the FORMULA: volume=length*width*height
You cannot.First, rectangular is an adjective and there is no associated noun so the question does not specify whether it is about a rectangular pyramid, a rectangular bipyramid, a rectangular prism or some other rectangular figure.Second, in order to find the weight of an object, you need the volume of the shape, the density of its material and the local force of gravity. The volume of the shape requires length and width as well as the height so the available information is hopelessly inadequate.
if the pool is rectangular, then the formula of base X height X depth will do well
The event E must be well defined.
Yes. It doesnt have to be a irregular even though sometimes it is easier just to do the math... for a rectangular object. l x w x h= volume
You need the total volume as well, then divide that successively by width and length
It is not enough to know the wood is rectangular, you need to know the measurements of the rectangle as well as the thickness. When these are converted to their equivalent measures in metres, the volume is length * width * thickness.
It depends on the shape.
well...if it's doubled then its doubled (just treat it the same)