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The length of a rectangle is 2 inches greater than the width The area is 80 inches2. Find the length of the rectangle?
Wiki User
∙ 13y ago
Let the length be x+2 and the width be x:
(x+2)*x = 80
x2+2x = 80
x2+2x-80 = 0
Solving the above with the quadratic equation formula works out as:
x = -10 or x = 8, so it must be the latter because dimensions can't be negative.
Therefore: length = 10 inches
Wiki User
∙ 13y ago
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The length of a rectangle is 2 inches greater than the width The are is 80 inches2 Find the length of the rectangle?
Let the length be x+2 and the width be x: (x+2)*x = 80 inches2 x2+2x = 80 Rearrange the equation into a quadratic: x2+2x-80 = 0 Solve by factoring or with the help of the quadratic equation formula: (x+10)(x-8) = 0 So x = -10 or x = 8 it must be the latter because the dimensions can't be negative. Therefore: length = 10 inches and the width = 8 inches
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12
The length of a rectangle is 2 inches greater than the width The are is 80 inches2 Find the length of the rectangle?
Let the length be x+2 and the width be x: (x+2)*x = 80 inches2 x2+2x = 80 Rearrange the equation into a quadratic: x2+2x-80 = 0 Solve by factoring or with the help of the quadratic equation formula: (x+10)(x-8) = 0 So x = -10 or x = 8 it must be the latter because the dimensions can't be negative. Therefore: length = 10 inches and the width = 8 inches
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