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Let L be the length of the rectangle and W the width, then

L = 2W - 3.

The perimeter = 2L + 2W = 2(2W - 3) + 2W = 6W - 6

But the perimeter measures 18"so, 6W - 6 = 18 : 6W = 24 : W = 4

The width of the rectangle is 4".

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Q: The length of a rectangle is 3 inches less than twice the width if the perimeter or the rectangle is 18 inches find the width of the rectangle?
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