w= width
w+4=length
2(w+l)= perimeter
2(w+w+4)=32 substitution
2(2w+4)=32
4w+8=32 distributive property
4w=32-8 subtraction property of equality
4w=24
w=6 division property of equality
length is 6+4 or 10cm.
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The perimeter of a rectangle is found by the following formula: (Length x 2) + (Width x 2) or Length + Length + Width + Width.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
8 length 8 width
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
The length of the length will be 5 and the width will be 25.
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
The perimeter of a rectangle is found by the following formula: (Length x 2) + (Width x 2) or Length + Length + Width + Width.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
you need length and width length multiply width = area length + length + width + width = perimeter
Length 17 cm. Width 10 cm.