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Q: The length of a rectangle is 5 in more than its width the perimeter of the rectangle is 42in what is the length of the rectangle?

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42in

Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764

13 in

One that is 3 ft 6 inches in length!

42in.

Forty-two.

Average Depth = Deep End (feet) + Shallow End (feet) divide by 2 Rectangular / Square Pool: Length (feet) x Width (feet) x Average Depth x 7.5 = Total gallons Circular Pool: Diameter x 2 x Average Depth x 7.5 = Total gallons Oval Pool: Max Length (feet) x Max Width (feet) x Average Depth x 7.5 = Total gallons Kidney Shaped Pool: Width of Shallow End (feet) + Width of Deep End (feet) x Length of Pool x 0.45 x Average Depth x 7.5 = Total gallons Free Form Pool: Max Length (feet) x Max Width (feet) x Average Depth x 7.5 = Total gallons See the related link for further information.

Not too sure of the question but using Pythagoras' theorem may help in finding the solution.

-for 16:9 aspect ratio the width would be around 36.5 in, plus the boarder of the TV -for 4:3 aspect ratio the width would be around 33.6 in, plus the boarder of the TV Geometry- - 16x9, the hypotenuse = 18.36 - hypotenuse of a 42in tv is 42 - the ratio b/t the TVs is 42/18.36 or 2.28 -width of 16:9 TV = 16, 16(2.28) ~ 36.5 -same process with any other aspect ratio

Assuming your pool is round about 800 gallons.

12in.= 1 foot, therefore 42in= 31/2feet

1ft = 12in 3.5ft = 3.5 x 12in = 42in

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