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Suppose the middle number is x. The smallest is x-1, the largest is x+1.

So their sum is x-1 + x + x+1 = 3x

ie 3x = 384 so that x = 128

So the three integers are 127, 128 and 129.

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14y ago
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Q: The numbers on three adjoining lockers are consecutive integers whose sum is 384 Find the integers?
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