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If that's the case, then the odds of the visiting team of winning is 1 to 3.

Q: The odds of a home team winning a football game are 3 to 1. What is the probability that the visiting team will win?

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The probability of winning two games with the same probability of 0.8 can be calculated by multiplying the probability of winning the first game (0.8) by the probability of winning the second game (0.8). Therefore, the probability is 0.8 * 0.8 = 0.64, or 64%.

If the odds are 179 to 2, the probability of winning is 0.01105, or; the chance of winning is 1.11%

Probability could be used in a sport to test or experiment the chances of getting an injury or losing/winning a game.

1 in 4,782,969

1 over 10,000

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The probability of winning two games with the same probability of 0.8 can be calculated by multiplying the probability of winning the first game (0.8) by the probability of winning the second game (0.8). Therefore, the probability is 0.8 * 0.8 = 0.64, or 64%.

As of Nov 3 2010, they have a 3% chance of playing in the National Championship Game.

If the odds are 179 to 2, the probability of winning is 0.01105, or; the chance of winning is 1.11%

The remaining 1 over 3 is the probability of losing.

The probability is 0.416667 or 41.67%

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the probability of winning that is the number you get over the total number of times you play the round!!!!!!!!!!!!for example: if i flipped the spoon two times, and you were supposed to flip 18 times, then the probability of winning is 2/18, which reduces to 1/9.

Probability could be used in a sport to test or experiment the chances of getting an injury or losing/winning a game.

If the game is fair, it is 1/3.

10,000,000 to one.

1 in 4,782,969

BYU currently holds the longest home game winning streak in college football with 18 wins