x = 2, y = 1
Y=-1/2(x)
what is the solution of x-5y=10 and 2x-10y=20
2
8x - 10y = 27x - 5y = 13First, we need to eliminate one of the variables. For this, we would like to have them with the same coefficient but different sign. We can do this if we multiply by -2 the second equation.8x - 10y = 2-2(7x - 5y) = -2(13)8x - 10y = 2-14x +10y = -26Now, we can add both equations, and solve for x.(8x - 10y) + (-14x + 10y) = (2) + (-26)(8x - 14x) +(-10y + 10y) = (2 - 26)-6x = - 24-6x/-6 = - 24/-6x = 4Substitute 4 for x in the first equation:8x - 10y = 28(4) - 10y = 232 - 10y = 232 - 32 - 10y = 2 - 32-10y = -30-10y/-10 = -30/-10y = 3Thus, the solution of the system is (4, 3).Check:
It's a linear expression in two unknowns.It can be simplified a little bit:18x + 14y + 3x - 10y = 21x + 4y
10y plus 40 equals 50y.
10y = 9y + 4, so y = 4
Y-8x plus 9y equals 10y-8x.
yes that is correct
10y= 6y+5+3y 10y=6+9y y=6
Y=-1/2(x)
x = 6y = 89x + 10y = 9(6) + 10(8) = 54 + 80 = 134
10y = 2y - 6y + 7 10y =-4y + 7 10y +4y = 7 14y = 7 y = 1/2 = .5
y= 3/6 which reduces to 1/2
X=7 y=5
(2, 1)
y = ½ (6y = 3)