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Assuming you replace the cube each time its drawn... 1/2 x 1/2 x 1/2 = 1/8

Q: The probability of drawing a green cube is one half. What is probably of drawing green cube on first three draws?

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1/48 if there aren't jokers

2 in 52, or 1 in 26, or about 0.03846.

There are 26 red cards and 13 spades in a standard deck of 52 cards. The probability of drawing a red card or a spade in one draw is, therefore, 39 in 52. If you draw twocards, and the first is not red or spade, then the probability on the second draw is 39 in 51, otherwise it is 38 in 51.Combining these two probabilities is easy. Just turn the problem around, and ask what is the probability of drawing two clubs? The answer is (13 in 52) times (12 in 51), which is 156 in 2652, or 1 in 17. Flip that answer over by subtracting it from 1, and you get a probability of drawing a red card or a spade in two draws of 16 in 17, or about 0.9412.

The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.

The probability of drawing 2 cards that are two's from a standard deck of 52 playing cards is 1 in 221. The probability of drawing the first two is 4 in 52 or 1 in 13. The probability of drawing the second two is 3 in 51. Multiply those two probabilities together and you get 3 in 663, or 1 in 221.

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The probability of drawing aces on the first three draws is approx 0.0001810

4/221

1/48 if there aren't jokers

2 in 52, or 1 in 26, or about 0.03846.

58.3333333 % chance of drawing a girl's name.

There are 26 red cards and 13 spades in a standard deck of 52 cards. The probability of drawing a red card or a spade in one draw is, therefore, 39 in 52. If you draw twocards, and the first is not red or spade, then the probability on the second draw is 39 in 51, otherwise it is 38 in 51.Combining these two probabilities is easy. Just turn the problem around, and ask what is the probability of drawing two clubs? The answer is (13 in 52) times (12 in 51), which is 156 in 2652, or 1 in 17. Flip that answer over by subtracting it from 1, and you get a probability of drawing a red card or a spade in two draws of 16 in 17, or about 0.9412.

The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.

Let's call the chance of drawing a 9 on the first draw P(A). Since there are four 9s, P(A) is 4/52. Probability of not drawing a 9 is 1-(4/52). Each draw is independent so we multiply the probabilities. The probability of EXACTLY one 9 in two draws if P(A)P(1-A)=12/169 which is a about .071

The probability of drawing three black cards from a standard pack depends on:whether the cards are drawn at random,whether or not the drawn cards are replaced before the next card is drawn,whether the probability that is required is that three black cards are drawn after however many draws, or that three black cards are drawn in a sequence at some stage - but not necessarily the first three, or that the first three cards cards that are drawn are black.There is no information on any of these and so it is not possible to be certain about the answer.The probability of drawing three black cards, in three random draws - without replacement - from a standard deck, is 0.1176 approx.

In the first two draws, the probability is 1/15.

The probability of drawing a red card and a spade in two cards is the probability of drawing a red card multiplied by the probability of drawing a spade, multiplied by 2 (as it doesn't matter which way around they are drawn). The probability of drawing a spade is 1/13 as there are 4 spades and 52 cards. The probability of drawing a red card after this is 26/51 if the spade was black, and 25/51 if the spade was red. This averages at 51/102 Multiply these probabilities together and then multiply by two and we get 51/663 which can be simplified to 1/13

The probability of drawing a spade in a standard 52 card deck is 13 in 52, or 1 in 4. The probability of drawing a second spade, assuming the first spade was not replaced back into the deck, is 12 in 51. The probability, then, of drawing two spades is the product of those two probabilities, or 12 in 204, or 1 in 17.