Wiki User
∙ 13y ago1 in 36
Wiki User
∙ 13y ago1 out of 6 times,or 16.67% probability.
It is 0.9034, approx.
The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954
One.
The probability of getting a sum of 2 at least once is 0.8155
1 out of 6 times,or 16.67% probability.
It is 0.9034, approx.
The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954
One.
0.3 * 0.3 = 0.09
The probability of getting a sum of 2 at least once is 0.8155
1:6
In one roll the probability is 1/36.
It is 2/6 = 1/3
The probability of getting a 7 on one roll of a die is zero.If you meant to ask about two dice, the probability is 6 in 36, or 1 in 6.
The answer depends on how often you roll it! For one roll it is 1/6 but the probability increases to a near certainty as you increase the number of rolls.
you will land on 1 or 6 5/6 times