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Hollis Langosh

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Q: The quadratic equation whose roots are 1 and -1?
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Which equation has imaginary roots a.x2-1 equals 0 b.x2-2 equals 0 c.x2 plus x plus 1 equals 0 d.x2-x-1 equals 0?

To find which has imaginary roots, use the discriminant of the quadratic formula (b2 - 4ac) and see if it's less than 0. (The quadratic formula corresponds to general form of a quadratic equation, y = ax2 + bx + c)A) x2 - 1 = 0= 0 - 4(1)(-1) = 4Therefore, the roots are not imaginary.B) x2 - 2 = 0= 0 - 4(1)(-2) = 8Therefore, the roots are not imaginary.C) x2 + x + 1 = 0= 1 - 4(1)(1) = -3Therefore, the roots are imaginary.D) x2 - x - 1 = 0= 1 - 4(1)(-1) = 5Therefore, the roots are not imaginary.The equation x2 + x + 1 = 0 has imaginary roots.


what is the correct quadratic formula?

The roots of the equation [ Ax2 + Bx + C = 0 ] arex = 1/2A [ -B ± sqrt(B2 - 4AC) ]


Can you solve 3x2-x equals -1?

Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.


What are the steps to solving a quadratic equation?

In general, there are two steps in solving a given quadratic equation in standard form ax^2 + bx + c = 0. If a = 1, the process is much simpler. The first step is making sure that the equation can be factored? How? In general, it is hard to know in advance if a quadratic equation is factorable. I suggest that you use first the new Diagonal Sum Method to solve the equation. It is fast and convenient and can directly give the 2 roots in the form of 2 fractions. without having to factor the equation. If this method fails, then you can conclude that the equation is not factorable, and consequently, the quadratic formula must be used. See book titled:" New methods for solving quadratic equations and inequalities" (Trafford Publishing 2009) The second step is solving the equation by the quadratic formula. This book also introduces a new improved quadratic formula, that is easier to remember by relating the formula to the x-intercepts with the parabola graph of the quadratic function.


What does it mean when the graph of a quadratic function crosses the x axis twice?

When the graph of a quadratic crosses the x-axis twice it means that the quadratic has two real roots. If the graph touches the x-axis at one point the quadratic has 1 repeated root. If the graph does not touch nor cross the x-axis, then the quadratic has no real roots, but it does have 2 complex roots.

Related questions

What are the roots of the quadratic equation below?

That depends on the equation.


What can the discriminant tell you about a quadratic equation?

It can tell you three things about the quadratic equation:- 1. That the equation has 2 equal roots when the discriminant is equal to zero. 2. That the equation has 2 distinctive roots when the discriminant is greater than zero. £. That the equation has no real roots when the discriminant is less than zero.


What roots of the quadratic equation are equivalent to xx-x-12 equals 0?

-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12


What is true of the discriminant?

It discriminates between the conditions in which a quadratic equation has 0, 1 or 2 real roots.


What are the roots of the polynomial x2 plus 3x plus 5?

You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).


What are the roots of the equation 2xsquare -4x -1 0?

I suggest you apply the quadratic formula (a = 2, b = -4, c = -1).


What are the roots of the quadratic equation x squared minus 3x plus 2 equals 0?

Use the quadratic formula, with a = 1, b = -3, c = 2.


Does every quadratic equation have 2 roots?

No. The quadratic may have what's known as repeated roots, where it only has one root; for example, x2 + 2x + 1 = (x+1)(x+1) = 0 has only one root at x = -1. It always has roots, but can be imaginary roots, also, when no part of the graph intersects the X axis.


If one of the roots of the quadratic equation is 1 plus 3i what is the other root?

The answer to the question, as stated, is that the other root could be anything. However, if all the coefficients of the quadratic equation are real numbers, then the other root is 1 minus 3i.


What 2 values of x are roots of the polynomial x2 plus 3x-5?

You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).


Is it true The Quadratic Formula can be used to solve any quadratic equation?

No. Well, it depends what you mean with "any quadratic equation". The quadratic formula can solve any equation that can be converted to the form: ax2 + bx + c = 0 Note that it involves only a single variable. There are other limitations as well; for example, no additional operations. If a variable, or the square of a variable, appears in the denominator (1/x, or 1/x2), then some might say that it is "quadratic", but it might no longer be possible to convert the equation into the standard form named above. Similarly, if you have additional operations such as square roots or higher roots, trigonometric functions, etc., it might not be possible to convert the equation into a form that can be solved by the quadratic formula.


Which equation has imaginary roots a.x2-1 equals 0 b.x2-2 equals 0 c.x2 plus x plus 1 equals 0 d.x2-x-1 equals 0?

To find which has imaginary roots, use the discriminant of the quadratic formula (b2 - 4ac) and see if it's less than 0. (The quadratic formula corresponds to general form of a quadratic equation, y = ax2 + bx + c)A) x2 - 1 = 0= 0 - 4(1)(-1) = 4Therefore, the roots are not imaginary.B) x2 - 2 = 0= 0 - 4(1)(-2) = 8Therefore, the roots are not imaginary.C) x2 + x + 1 = 0= 1 - 4(1)(1) = -3Therefore, the roots are imaginary.D) x2 - x - 1 = 0= 1 - 4(1)(-1) = 5Therefore, the roots are not imaginary.The equation x2 + x + 1 = 0 has imaginary roots.