M = 11J/6 ; J = 12S so S = J/12; M + J + S = 105 (117 - 3 x 4)
11J/6 + J + J/12 = 105
22J + 12J + J = 1260
35J = 1260 so J = 36
Mom is 66, Jess is 36 and her son is 3.
Total ages at present = 42 Total ages in 10 years = 52 Fractions then 15/26 x 52 and 11/26 x 52, ie 30 and 22 so ages now 25 and 17
Ages are 25 and 20, so difference = 5 years.
The sum of the ages of husband and his wife is four times the sum of the ages of their children.Four years ago,the ratio of the sum of their ages of their to the sum of the ages of their children was 18:1 two years hence the ratio will be 3:1. How many children do they have.
Men to women ratio is termed as sex-ratio. The total sex-ratio of Nicaragua in 2004 was 1 male(s)/female. But sex-ratio is also calculated at different ages, so sex-ratio in Nicaragua in age-group is as follows in 2004.at birth: 1.05 male(s)/femaleunder 15 years: 1.04 male(s)/female15-64 years: 0.99 male(s)/female65 years and over: 0.78 male(s)/femaletotal population: 1 male(s)/female (2004 est.)
6:3 :) i learnt about ratios to day in maths
It will be better if you ask this question to Sachin...
S= present age of sameet M = present age of meeakshi] Currently: (S/M)=(4/5) Therefore: S*5= M*4 In 6 years: (S+6)/(M+6) = (14/17) S*17 + 18 = M*14 Solving for S: plug in M=S*(5/4) S*17 + 18 = S*(5/4)*14 = (S*35/2) 18 = S*(1/2) S=36 and therefore M = 45 In 12 years(after the current 6): they will be 54 and 63 respectively. So the ratio of their ages will be 18 to 21
42/4 = 10.510.5*3=31.5
There isn't really an exact number of years ago, but it was probably about 1500 years ago.
because it did.
Given a ratio, a percentage is the numerator of an equivalent ratio whose denominator is 100.
The ratio of the population ages 15 or over is 1.06 males per female.