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No, squares do not represent perimeters.
The area of similar figures is proportional to the square of any linear measurement. (And all linear measurements are directly proportional.) Thus, if the ratio of the perimeters is 5/4, the ratios of the lengths of sides is also 5/4. The ratio of the areas, on the other hand, is (5/4)2, so you can simply multiply the area of the smaller square by this factor.
If a square's perimeter is 16.4 - it's sides are 4.1
A Square which has been divided up into 24 smaller squares.
You cannot. If you are dividing any square into equal sized squares, then the number of these smaller squares must be a square number.
Assume square A with side a; square B with side b. Perimeter of A is 4a; area of A is a2. Perimeter of B is 4b; area of B is b2. Given the ratio of the perimeters equals the ratio of the areas, then 4a/4b = a2/b2; a/b = a2/b2 By cross-multiplication we get: ab2 = a2b Dividing both sides by ab we get: b = a This tells us that squares whose ratio of their perimeters equals the ratio of their areas have equal-length sides. (Side a of Square A = side b of Square B.) This appears to show, if not prove, that there are not two different-size squares meeting the condition.
Yes, they're both squares.
The length of each side of the smaller squares is 2.475 cm
If the length of each side of the bigger squares is x times the length of the side of the smaller square, then the area of the bigger square is x2 times the area of the smaller square.
five. four smaller squares in a 2x2 formation, which then make up a larger square.
If an equilateral triangle and a square have equal perimeters, then the ratio of the area of the triangle to the area of the square is 1:3.
There are 5 squares in a 2 by 2 grid if the large square enclosing all four smaller squares is included in the count.