y = 3x+8
x + y = 72
x = 16
y = 56
54
45
57
a=58.4615 b=5.2308 c=41.3076
= The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers? =
54
45
57
a=58.4615 b=5.2308 c=41.3076
= The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers? =
Take two numbers. Throw (the first number) into a box (the second number) times. The total amount in the box is then the product of the two numbers.
Add the first to itself.
four times a number is 6 more than three times a second number while 8 times the first number is 22 less than 7 times the second number. find the 2 numbers
The numbers are 14, 16 and 18.
25 and 14
This problem asks us to find 2 numbers, n1 and n2, with the following relations between them: * n2 = 4 n1 * n1 + n2 = 45 Substituting the first equation into the second one gives us: * n1 + 4n1 = 45 which gives us * n1 = 9. We can now use this solution to find n2 with the first equation * n2 = 4 n1 = 36 So the first number is 4, the second number is 36.
Let the two numbers be x and y, then:Twice the first equals three times the second: 2x = 3yThree times their difference exceeds the second by 13: 3(x - y) = y + 13From equation (1) it is clear the first number (x) is greater than the second (y), so their difference is x - y.Equation (2) can be rearranged:3(x - y) = y + 13→ 3x - 3y = y + 13→ 3x = 4y + 13This gives two simultaneous equations:2x - 3y = 03x - 4y = 13which can then be solved to find the two numbers (x and y).