First you see, two digit no consist of tens place and unit place assume that two digit no be 10x+y
Next sum of those digit is 10 assume it as x+y=10 or x+y-10=0 assume as equation 1
Next question says if you reverse those two digit no (10x+y) it will be 10y+x just changing unit place and tens place. Now as per question
If you reverse, first assumed two digit no . It will be 18 more than the first we assumed two digit
That is 10y+x=10x+y+18
10y-10x+x-y=18
9y-9x=18
9(y-x)=18
Y-x=2 or y-x-2=0 assume it as equation 2
Combine equation 1and 2 that means 1=2
y-x-2=x+y-10
y-y-x-x-2+10=0
-2x+8=0
-2x=-8
X=4 substitute this x in equation 1
x+y=10
4+y=10
Y=6
Sum of these digits that is x+y; 4+6=10
That two digit no 10x+y=10*4+6=46
First we assumed is original no 10x+y that is 46
Original no is 46
To begin with, let's represent the ten's digit with x. Then, we know that the one's digit is (10-x), because the sum of the digits is 10. Since the value of the ten's is 10 times more than the digit, we multiply it by 10. Now we have the original number: 10x+10-x. We can simplify it into 9x+10. For the reversed number, the digits switch spots, so now we multiply the one's by 10. The reversed # is 10(10-x)+x, which could be simplified into 100-9x.To get an equation you have to balance the two sides. For that, you need to add 18 to the original # to make it equal to the reversed #.
9x+10+18=100-9x
9x+9x=100-28
18x=82
x=82/18
x=4
The original number is 46.
The reversed number is 64.
CHECK: 64-46=18
IT WORKS!!!
192
Possibility of two digit no whose sum is 17 89 and 98 Reverse of 89 is 98. 98 is 9 less than the original no 89. 89 is original no
11yrs.
Find a four digit number whose digits will be reversed when multiplied by nine?
Possibility of two digit no whose sum is 10 19,28,37,46,55,64,73,82,91 Now add 54 to each no mentioned above 73,82,91,100,109,118,127,136,145 See after 1st comma 28 and 82 Reverse of 28 is 82. That no 82 is 54 more than the no 28. So 28 is the original
The number is 36
17
192
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
five digits number when you multiply by four is the same the number when you reversed it is 21978*4 = 87912
Possibility of two digit no whose sum is 17 89 and 98 Reverse of 89 is 98. 98 is 9 less than the original no 89. 89 is original no
An eight digit number with one zero cannot remain the same when its digits are reversed. It must have an even number of 0s.
after 11yrs.
11yrs.
47 Impossible problem!
Find a four digit number whose digits will be reversed when multiplied by nine?
45