Interior angles of any quadrilateral always total 360o.
I'm not sure if you mean interior or exterior angles, so I'll give you an answer for both.For interior angles:The sum of the measures of the *interior* angles of a quadrilateral is always 360 degrees. To understand why this is true, recall that the sum of the interior angles of a triangle is 180 degrees. Now, in any quadrilateral, we can draw a diagonal, splitting it into two triangles.So, the sum of the interior angles of the quadrilateral will be the sum of all of the interior angles of the two triangles, in other words, 2x180.In general, an n-gon can be divided into n-2 triangles, so the sum of the interior angles of an n-gon is 180x(n - 2) = 180xn - 360For exterior angles:The sum of the exterior angles of any closed, convex figure will be 360 degrees. So, if the quadrilateral is convex (isn't bent inwards) the sum of the exterior angles will be 360 as well.
The sum of the interior angles of a quadrilateral is 360 degrees (not 180). The sum of the exterior angles is also 360 degrees. Whether the quadrilateral is convex or concave is not relevant.
It depends on convex WHAT!
No. In a convex polygon the sum of the interior angles is (n-2)*180 deg where n is the number of interior angles. In a non-convex polygon this is not necessarily true.
It is a convex quadrilateral, as the remaining angles could be any two angles with a sum of 180 degrees.
Hmmm... how bout 360 degrees ?
What is the sum of the measures of the angles of a convex quadrilateralwill this property hold if the quadrilateral is not convex?
I'm not sure if you mean interior or exterior angles, so I'll give you an answer for both.For interior angles:The sum of the measures of the *interior* angles of a quadrilateral is always 360 degrees. To understand why this is true, recall that the sum of the interior angles of a triangle is 180 degrees. Now, in any quadrilateral, we can draw a diagonal, splitting it into two triangles.So, the sum of the interior angles of the quadrilateral will be the sum of all of the interior angles of the two triangles, in other words, 2x180.In general, an n-gon can be divided into n-2 triangles, so the sum of the interior angles of an n-gon is 180x(n - 2) = 180xn - 360For exterior angles:The sum of the exterior angles of any closed, convex figure will be 360 degrees. So, if the quadrilateral is convex (isn't bent inwards) the sum of the exterior angles will be 360 as well.
The sum of the interior angles of a quadrilateral is 360 degrees (not 180). The sum of the exterior angles is also 360 degrees. Whether the quadrilateral is convex or concave is not relevant.
the sum of the interior angles of a convex 45-gon is 7740.
360 degrees - and that is true for any quadrilateral or convex four sided shape.
The sum of the interior angles of a quadrilateral is 360 degrees
It depends on convex WHAT!
a convex polygon has 6 sides . What is the sum of the measure of its interior angles?
No. In a convex polygon the sum of the interior angles is (n-2)*180 deg where n is the number of interior angles. In a non-convex polygon this is not necessarily true.
It is a convex quadrilateral, as the remaining angles could be any two angles with a sum of 180 degrees.
the sum of the interior angles of a 35-gon.