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The sum of the squares of three consecutive odd integers is 83Find the integers?
Wiki User
∙ 15y ago
let's try to construct a formula for this problem
we can define the first odd number as X.then the other two numbers would be X+2 and X+4
then the formula would be
X^2+(X+2)^2+(X+4)^2=83
Now simplify the sum
X^2+(X^2+4X+4)+(X^2+8X+16)-83=0
Now the sum is in quadratic form
3X^2+12X-63=0
Divide by 3,
X^2+4X-21=0
So the factors would be
(X-3),(X+7)
then the X equals to 3 because we only consider the positive integers
therefore three constructive odd number of which sum of squares equal to 83 is 3,5 and 7
9+25+49=83
thanks
Mafaz ansar
mafazansar@Yahoo.com
Wiki User
∙ 15y ago
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