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The sum of three consecutive even integers that give you 151 and tha sum of three consecutive odd integers that give you 150?
Wiki User
∙ 15y ago
There are no such answers. The sum of even numbers is even. The sum of odd numbers could be even, but the sum of three consecutive odd numbers is always odd. One could swap the questions to get potentially answerable questions: Sum of 3 consecutive EVEN integers = 150 48 + 50 + 52 = 150 unfortunately, we can already see that if we were to make these odd integers (add 1 to each), we would get 153, not 151. Sum of 3 consecutive ODD integers = 151 49 + 51 + 53 = 153 47 + 49 + 51 = 147 We can see that, whenever we slide our three consecutive integers up one, we raise the value of the sum up 3, and if we jump from odd to odd, or even to even, we raise each integer by 2, so we raise the sum by 6.
Wiki User
∙ 15y ago
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What are three consecutive even integers whose sum is 32?
That isn't possible; three consecutive integers, or three consecutive positive integers, always have a sum that is a multiple of 3. In general, you can solve this quickly by trial and error. In this case, you will quickly find that a certain set of three consecutive integers will give you a sum that is TOO LOW, while the next-higher even integers will give you a sum that is TOO HIGH. You can also write an equation and solve it: n + (n + 2) + (n + 4) = 32. If you solve it, you will find that the solution is fractional, not integral.
What three consecutive numbers multiply together to give you 990?
The numbers are 9, 10 and 11.
Give example of closure property?
Add two positive integers and you ALWAYS have a positive integers. The positive integers are closed under addition.
What are two consecutive numbers which give the product of 3906?
The numbers are 62 and 63.
What 2 consecutive numbers which give a product of 8556?
The numbers are 92 and 93.
What are three consecutive odd integers whose sum is 336?
The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.
What are three consecutive even integers whose sum is 32?
That isn't possible; three consecutive integers, or three consecutive positive integers, always have a sum that is a multiple of 3. In general, you can solve this quickly by trial and error. In this case, you will quickly find that a certain set of three consecutive integers will give you a sum that is TOO LOW, while the next-higher even integers will give you a sum that is TOO HIGH. You can also write an equation and solve it: n + (n + 2) + (n + 4) = 32. If you solve it, you will find that the solution is fractional, not integral.
How would you find four consecutive even integers whose sum is four?
You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.
What are three consecutive integers of -363?
Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.
Does the sum of three consecutive even numbers give you an odd or even number?
It will always give an even number, as adding any amount of even numbers always results in an even number.
Find two consecutive integers such that the sum of the smaller and 3 times the larger is 330?
x + 3(x +1) = 330 4x = 327 which doesn't give an answer in integers. If question should read "consecutive ODD integers" the answer would be 81 and 83.
What two consecutive odd integers squares subtract to give you 24?
72 - 52 = 49 - 25 = 24
What are 3 consecutive even integers whose sum is 210?
Here's how you can work it out: First, let "x" be the first of those three numbers. We know that those numbers are three consecutive even integers, which tells us that the other numbers are "x + 2" and "x + 4". We also know that the three of them added together give us 210, so we can say: x + (x + 2) + (x + 4) = 210 ∴ 3x + 6 = 210 ∴ 3x = 204 ∴ x = 68 We now know that the lowest number is 68, which tells us that the other two must be 70 and 72. To check that, we simply add them together: 68 + 70 + 72 = 210 which confirms our answer.
Find three even consecutive integers where the largest is 20 less than three times the smallest?
First, you give each integer a value. X or N are common. The integers would then be N, N + 2, N + 4.That would make 3(N) - 20 = N + 4. Subtract N from both sides and add 20, so you get:3N - N (=2N) - 20 + 20 = N - N + 4 + 20.That leaves you with 2N = 24, and if you divide both sides by 2, that gives you:N = 12.Thus, the three integers are:12, 14, 16
What are three consecutive integers that equal 171?
I'm assuming this is supposed to say: "What are three consecutive integers that add together to equal 171?"This could also be "What are three consecutive integers that multiply together to equal 171?"I will do both.For the addition caseThink of "three consecutive integers" as the expressions x, x+1, and x+2. For any value of x, these three expressions will give that number, the number that is one greater than it, and the number that is two greater than it. So, the expression x+(x+1)+(x+2) is the general sum of three consecutive integers. Also possible is the expression x+(x-1)+(x-2), which are still three consecutive integers. So, this is a simple equation:x+(x+1)+(x+2)=171x+x+1+x+2=1713x+3=1713x=168x=168/3x=56Since x=56, x+1=57 and x+2=58So the three numbers are 56,57,and 58You can check this answer by adding the three numbers together. I'll bet they equal 171.For the multiplication case:Refer to the explanation for the addition case, but instead of the end expression being x+(x+1)+(x+2), it is now the multiplication of the three integers, meaning the expression is (x)(x+1)(x+2), so we get: (x)(x+1)(x+2)=171(x)(x2+3x+2)=171x3+3x2+2x=171I'll admit right now I don't know a simple way to solve this equation, which hints to me that addition was the intent of the question, but this equation can be solved by plotting the equationsy=x3+3x2+2xy=171and finding their point(s) of intersection. The value comes out to be approximately 4.6106, which means that the numbers 4.6106, 5.6106, and 6.6106 will multiply to equal approximately 171 (but not exactly). No exact answer is really possible here.
What three consecutive numbers give you the sum of 15?
The numbers are 4, 5 and 6.
What 2 consecutive even numbers give you a dividend of 2?
1
