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There are no such answers. The sum of even numbers is even. The sum of odd numbers could be even, but the sum of three consecutive odd numbers is always odd. One could swap the questions to get potentially answerable questions: Sum of 3 consecutive EVEN integers = 150 48 + 50 + 52 = 150 unfortunately, we can already see that if we were to make these odd integers (add 1 to each), we would get 153, not 151. Sum of 3 consecutive ODD integers = 151 49 + 51 + 53 = 153 47 + 49 + 51 = 147 We can see that, whenever we slide our three consecutive integers up one, we raise the value of the sum up 3, and if we jump from odd to odd, or even to even, we raise each integer by 2, so we raise the sum by 6.

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Q: The sum of three consecutive even integers that give you 151 and tha sum of three consecutive odd integers that give you 150?

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The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.

That isn't possible; three consecutive integers, or three consecutive positive integers, always have a sum that is a multiple of 3. In general, you can solve this quickly by trial and error. In this case, you will quickly find that a certain set of three consecutive integers will give you a sum that is TOO LOW, while the next-higher even integers will give you a sum that is TOO HIGH. You can also write an equation and solve it: n + (n + 2) + (n + 4) = 32. If you solve it, you will find that the solution is fractional, not integral.

You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.

Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.

It will always give an even number, as adding any amount of even numbers always results in an even number.

x + 3(x +1) = 330 4x = 327 which doesn't give an answer in integers. If question should read "consecutive ODD integers" the answer would be 81 and 83.

72 - 52 = 49 - 25 = 24

The numbers are 4, 5 and 6.

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Here's how you can work it out: First, let "x" be the first of those three numbers. We know that those numbers are three consecutive even integers, which tells us that the other numbers are "x + 2" and "x + 4". We also know that the three of them added together give us 210, so we can say: x + (x + 2) + (x + 4) = 210 ∴ 3x + 6 = 210 ∴ 3x = 204 ∴ x = 68 We now know that the lowest number is 68, which tells us that the other two must be 70 and 72. To check that, we simply add them together: 68 + 70 + 72 = 210 which confirms our answer.

n x (n +1) = 40 =n^2 + n = 40 This does not have a solution in integers Even without the algebra you can quickly note that 7x6 is 42 which is too much and 6x5 is 30 which is too little so there is no solution.

First, you give each integer a value. X or N are common. The integers would then be N, N + 2, N + 4.That would make 3(N) - 20 = N + 4. Subtract N from both sides and add 20, so you get:3N - N (=2N) - 20 + 20 = N - N + 4 + 20.That leaves you with 2N = 24, and if you divide both sides by 2, that gives you:N = 12.Thus, the three integers are:12, 14, 16

Pick any three numbers which, multiplied together, give 24. They need not be integers.

Because different operations with different integers give different answers.

Add two positive integers and you ALWAYS have a positive integers. The positive integers are closed under addition.

The turkey. It's supposedly because they'd give you a turkey if you bowled three strikes in a row the week before Thanksgiving.

1 As whole numbers 2 As prime numbers 3 Arithmetical calculations without fractions or decimals

The maximum number of attempts in AIEEE is limited to 3 (three), in the consecutive years of passing the board exams.

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I'm assuming this is supposed to say: "What are three consecutive integers that add together to equal 171?"This could also be "What are three consecutive integers that multiply together to equal 171?"I will do both.For the addition caseThink of "three consecutive integers" as the expressions x, x+1, and x+2. For any value of x, these three expressions will give that number, the number that is one greater than it, and the number that is two greater than it. So, the expression x+(x+1)+(x+2) is the general sum of three consecutive integers. Also possible is the expression x+(x-1)+(x-2), which are still three consecutive integers. So, this is a simple equation:x+(x+1)+(x+2)=171x+x+1+x+2=1713x+3=1713x=168x=168/3x=56Since x=56, x+1=57 and x+2=58So the three numbers are 56,57,and 58You can check this answer by adding the three numbers together. I'll bet they equal 171.For the multiplication case:Refer to the explanation for the addition case, but instead of the end expression being x+(x+1)+(x+2), it is now the multiplication of the three integers, meaning the expression is (x)(x+1)(x+2), so we get: (x)(x+1)(x+2)=171(x)(x2+3x+2)=171x3+3x2+2x=171I'll admit right now I don't know a simple way to solve this equation, which hints to me that addition was the intent of the question, but this equation can be solved by plotting the equationsy=x3+3x2+2xy=171and finding their point(s) of intersection. The value comes out to be approximately 4.6106, which means that the numbers 4.6106, 5.6106, and 6.6106 will multiply to equal approximately 171 (but not exactly). No exact answer is really possible here.

The sum of two consecutive even numbers, when divided by two, will always give an odd number.... and that odd number is one more than the first number, and 1 less than the second number. 4 + 6 = 10 ..... 10 / 2 = 5 78 + 80 = 158 ..... 158 / 2 = 79 1222 + 1224 = 2446 ..... 2446 / 2 = 1223 ... and so forth As 626 / 2 = 313 ..... the numbers must be 312 and 314.

Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.

-- write the difference between the integers without regard to their signs -- give the difference the same sign as the larger of the two integers

I understand your question to read What are two integers that give a quotient of 3.15. If that is correct, one solution is 315/100.

(-3)(-2)(-6) = -36