Wiki User
∙ 7y agoThy are 8, 10 and 12.
Wiki User
∙ 7y agoTheir sum is three times the middle number.
You've come to the right place. The integers are: 2, 4, and 6
172
First, multiply the consecutive numbers. Your total will be the highest factor.
x + x + 1 + x + 2 = 3x + 3 = 3 times the middle number
Their sum is three times the middle number.
0,6,18,36,60,90,126,168, etc
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
The sum of 3 consecutive whole numbers is always equal to 3 times the middle number in that sequence.
x+(n+1)+3(n+2)= something then solve,
6
You've come to the right place. The integers are: 2, 4, and 6
172
5872345098234783904672083946728390752430689723409687298290843 theres your answer
249
The sum of three consecutive integers is -72
First, multiply the consecutive numbers. Your total will be the highest factor.