129 divided by 3 is 43, so the 3 consecutive integers having a sum of 129 are 42, 43, and 44.
The numbers are 41, 43 and 45.
There are none.
Suppose the middle number is x. The smallest is x-1, the largest is x+1. So their sum is x-1 + x + x+1 = 3x ie 3x = 384 so that x = 128 So the three integers are 127, 128 and 129.
They are: 41+43+45 = 129
The numbers whose sum is 129 are 41, 43 and 45.
129 divided by 3 is 43, so the three numbers are 41, 43, and 45.
They are 128, 129 and 130.
43+45+47=135. i had this question for my online math class. but i don't know how to make that into an equation. something like 3x+2...maybe.. here is how you do it: We need three consecutive odd integers so we will let the first one be x, the next is x+2 and then third is x+4 3x+6=135 3x=129 x-43 x+2=45 x+4=47 So the three numbers are 43, 45 and 47
X is the 1st integerX+1 would be the 2ndX+2 would be the 3rdX+(X+1)+(X+2) = 1323X+3=1323X+3-3=132-33X=129X=129/3 = 43So the consecutive integers are 43, 44, 45
128 and 130.
41,43,45 is the answer
The square root of 129 is 11.3578166916 An integer is a whole number (without fractions) Therefore: two integers could possibly be 10 and 1
The consecutive numbers that have a sum of 257 are 128 and 129.
Yes if it follows 128
The integers of 11 and 12
I believe that the University of Kentucky Wildcats holds the record for consecutive home court wins with 129.
The current most consecutive home wins is by the Kansas Jayhawks, which as of today is 37. no actually the most consecutive home wins is by the Kentucky Wildcats, which is 129 from 1943 to 1955!..
257/2 = 128.5 so 128 and 129
The least common factor of any set of integers is 1.
Rockwall County: 129 square miles.
129 is divisible by three, hence it is a composite number.