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Since the three integers are consecutive, let them be: m, m+1, and m+2.

Then:

  • m + (m+1) + (m+2) = 72
  • m + m + 1 + m + 2 = 3m + 3 = 72
  • 3(m+1) = 72
  • m+1 = 24
  • m = 23

So the three integers are: {23, 24, 25}. Check and they do in fact sum to 72.

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โˆ™ 2012-01-20 05:43:07
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Q: The sum of three consecutive integers is 72?
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The sum of the three consecutive integers?

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72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.


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Presumably the sum is -222, as defined by the question!


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The numbers are -26, -24, and -22. (all negative numbers can be considered odd or even).


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If sum were 75 the integers would be 24, 25 and 26, so the next lowest sum would be 23 + 24 + 25 ie 72. The answer is thus 23.


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The smallest of the three numbers is 22.


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The numbers are 71, 72 and 73.


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Another way of stating this is: n + (n+1) + (n+2) = 72; find n. Doing the math that works out to 3n + 3 = 72 or 3n = 69 at which point it should be obvious that n is 23 and the three integers are 23, 24, and 25.


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23, 24 & 25 :)


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