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Q: The sum of three consecutive integers is 72?

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The sum of three consecutive integers is -72

72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.

The even integers are 22, 24 and 26.

Presumably the sum is -222, as defined by the question!

The numbers are 23, 24 and 25.

The numbers are -26, -24, and -22. (all negative numbers can be considered odd or even).

23+24+25 = 72

The numbers are -21, -19, -17 and -15.

If sum were 75 the integers would be 24, 25 and 26, so the next lowest sum would be 23 + 24 + 25 ie 72. The answer is thus 23.

The smallest of the three numbers is 22.

72+73+74 = 219.

The numbers are 71, 72 and 73.

Another way of stating this is: n + (n+1) + (n+2) = 72; find n. Doing the math that works out to 3n + 3 = 72 or 3n = 69 at which point it should be obvious that n is 23 and the three integers are 23, 24, and 25.

The numbers are 22, 24 and 26.

Two consecutive odd integers are 'X' and 'X+2' . X + (X + 2) = 72 2X + 2 = 72 2X = 70 X = 35 X + 2 = 37

35 and 37.

Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72

There are none. However, the two odd numbers are 35 and 37.

23, 24 & 25 :)

Divide 72 by 3, this equals 24. This is the middle of the three numbers, so the answer is 23, 24 and 25. This works with finding any odd amount of consecutive numbers that sum up to another number.

If you mean three consecutive integers that add to 73, the answer is that there are no such numbers. 23+24+25 = 72 while 24+25+26 = 75

71+72=143

You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.

-8 -9

8 & 9

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