The numbers must total 888/8 ie 111. The middle number is 1/3 of 111 ie 37 so the three numbers are 36, 37 and 38 and multiples are 288, 296 and 304.
45, 60, and 75
15 and 18
There is no "most common multiple". To find all common multiples, you start by finding the least common multiple. All other common multiples are multiples of this least common multiple.
All common multiples of a set of numbers are multiples of the least common multiple. Therefore:* Use any standard procedure to find the LEAST common multiple. * Multiply that by 1, by 2, by 3, etc. to find additional common multiples.
There are three consecutive integers. Let's call the middle one x. The one before it is x - 1 and the one after it is x + 1. Adding them together equals 3x. That means that whatever they equal has to be a multiple of 3. Since 176 is not divisible by 3, you will not be able to find three consecutive integers with that total.
Let the second of the three consecutive multiples of 6 be 6n Then the first is 6n - 6 and the last is 6n + 6; and: (6n - 6) + 6n + (6n + 6) = 666 → 18n = 666 → n = 37 → the consecutive multiples of 6 which sum to 666 are 216, 222, 228
91
45, 60, and 75
15 and 18
To find its multiples!To find its multiples!To find its multiples!To find its multiples!
8, 12, 16 & 208 + 12 = 20
There is no "most common multiple". To find all common multiples, you start by finding the least common multiple. All other common multiples are multiples of this least common multiple.
2
Use the usual procedure to find the LEAST common multiple. Then, you can multiply that by 2, or by 3, or by 4, or by 5, etc., to get additional multiples.
111
Since they are both prime, just multiple them together (65) and find multiples of that. Common multiples of 5 and 13 are: 65*1 = 65 65*2 = 130 65*3 = 195 etc
8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.