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Q: The sum of three numbers in AP is 27 and their product is 405 Find the numbers?

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In exponents: 34*5 = 405

GM of two numbers is the square root of their product, in this case sqrt 2025 ie 45.

405 = 3 x 3 x 3 x 3 x 5

634 multiplied by 405 is 256,770.

The prime numbers (factors) of 405 are: 3 and 5

The geometric mean is 45.0

I assume you mean to find the prime factorization of 405. If so: 34 x 5

The numbers that go into 405 are 1, 3, 5, 9, 15, 27, 45, 81, 135, and 405.

All multiples of 405, which is an infinite number.

405

The product is 81,000

The least common multiple of the numbers 405 and 75 is 2,025.

To find the LCM of numbers you first need to break them down into their prime factors. In this case: 27=3x3x3 45=5x3x3 81=3x3x3x3 The next step is to disregard any duplicates when there are common prime factors. All numbers use two 3s so we can disregard 4 of them. Two numbers use an additional 3 so we can disregard 1 of them. This leaves us with: 5,3,3,3,3 Find the product of all of these numbers: 5x3x3x3=405 And that gives us the LCM. So the LCM of 27, 45, and 81 is 405.

45

Itself and any other of its factors.

Two: 3 and 5 405 expressed as the product of its prime factors in exponents = 34*5

Since 405 is positive, using one negative number forces one to actually use two negative numbers. The pair -1x-405 would work for instance.

Factors of 405 in pairs = 1 x 405, 3 x 135, 5 x 81, 9 x 45, 15 x 27.

It is: 3/8 of 1080 = 405

The Greatest Common Factor of the two numbers is 9. 288/9 = 32, 405/9 = 45.

9 x 45 = 405 To check your answer, you can take the final answer that you get and divide it by one of the numbers and see if you come out with the other number as an answer. For example, 405/9 = 45 and 405/45 = 9

1 x 405, 3 x 135, 5 x 81, 9 x 45, 15 x 27.

1 x 405, 3 x 135, 5 x 81, 9 x 45, 15 x 27.

405.

405 = 9 x 45