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Suppose the first number is x.

Then the second number is x-4 and the third is 4*x, or 4x

So, x+(x-4)+4x = 62 ie 6x-4= 62 or 6x = 66 or x = 11.

Then x-4 = 7 and 4x = 44

So the 3 numbers are 11, 7 and 44.

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Q: The sum of three numbers is 62 The second number is equal to the first number diminished by 4 The third number is four times the first What are the numbers?
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