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Q: The sum of two numbers is less than 17 The second number is 3 less than the first What are the possible values for the first of the two numbers?

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The values are : All even numbers and zero.

It is not possible to have any numbers lying between ONE number.

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What are all the possible whole number values for 7

Only if all values in the dataset are equal. Otherwise, it is impossible. If there are two numbers in the dataset, the median is the average of these two numbers. If there are three numbers, then the second number is the median or one number away from the maximum.

50 is an even number. To get even number by adding odd number of numerical values, ie three numbers that too all of them odd seems not at all possible.

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When a number is a multiple of 5, the possible values of the ones digit are zero and five.

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Individual digits within a number have place values, not whole numbers.

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All of the values added together, divided by the number of values.

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Since social security numbers have numeric values, a social security number is an example of a qualitative variable.

The average is the ratio between the sum of these values and the number of values.

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When a number is a multiple of 5, the possible values for the ones digit are zero and five.

In the simplest case, if A is the number of values a single element of a combination can have, and N is the number of elements in the combination, then the number of possible lock combinations is AN. For example: if you have a lock with a 4-digit numerical combination, any combination has 4 elements - the digits. Each digit can have 10 values - 0 through 9. So the total number of lock combinations is 104 or 10000. Another example: if you have the typical rotating combination padlock, a combination consists of three numbers, each of which can be 0-39. So the total number of combination shere is 403 or 64000. The calculation gets more complicated if the same number can't appear twice in the combination. In that case, there are A values for the first element, but only A-1 values for the second, A-2 values for the third, and so on. The formula in this case is A(A-1)(A-2)(...)(A-N+1) which can be written more concisely as A!/(A-N)!. For example: if you have the same rotating combination padlock as above, but know that the numbers in the combination are all different, there are 40*39*38 or 59280 possible combinations.

There are an infinite number of possibilities

Any even number.

Any even number.

Any even number.

Any even number.

Any even number.

Any even number.