If two similar rectangles have the widths 16m and 14cm what is the ratio of the perimiters?
If the 'ratio' (length/width) of one rectangle is the same number as (length/width) of the other one, then the two rectangles are similar.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
Only if they both have the same ratio of length to width. Since every square has the same ratio of length to width ( it's 1 ), all squares are similar. Gee, when you think about it, every regular polygon is similar to every other regular polygon with the same number of sides. I never realized that.
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
The factor pairs are the length and width of the rectangles.
If the 'ratio' (length/width) of one rectangle is the same number as (length/width) of the other one, then the two rectangles are similar.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
Only if they both have the same ratio of length to width. Since every square has the same ratio of length to width ( it's 1 ), all squares are similar. Gee, when you think about it, every regular polygon is similar to every other regular polygon with the same number of sides. I never realized that.
The ratio of their perimeters is also 45/35 = 9/7. The ratio of their areas is (9/7)2 = 81/63
If you are trying to find the ratio of the lengths of two similar rectangles, divide the length of one side of one rectangle by the corresponding side length of the other rectangle. To find the ratio between their volumes, divide the volume of one rectangle by the volume the other rectangle. To find volume, multiply the width of the rectangle by the length of the rectangle.
yes, all rectangles are in fact congruent. they're all congruent because its a ratio of sizes. if u have a rectangle with a length of 5 and a width of 2.5, and an another rectangle with a length of 10 and a width of 5, u have a ratio of sixes. the ratio would be 1:2. hope it helps (:
I can give the width of one of the rectangles. The first rectangle of area 15 cm2 and length of 5 cm has width of 3 cm. It is impossible to know the width of the other rectangle of area 60 cm2. However, if you had said that the two rectangles were similar, then the dimensions of the second rectangle would be 10 cm X 6 cm. But you didn't say that the two rectangles were similar; so there are infinite possibilities of what the dimensions of the second rectangle might be.
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
The factor pairs are the length and width of the rectangles.
There are infinitely many such rectangles.
20 inches
No, in general that is not true. For two similar figures it is true. But you can easily design two different figures that have the same perimeters and different areas, or the same area and different perimeters. For example, two rectangles with a different length-to-width ratio.