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There is a bag of marbles 10 are red 15 are purple and 25 are yellow what is the probability of picking a purple marble?
Wiki User
∙ 10y ago
3/10 or 0.3 is the probability of picking a purple marble.
Wiki User
∙ 10y ago
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A bag contains 6 purple and 7 white marbles two marbles are drawn at random one marble is drawn and not replaced what is the probability that the fist marble is white and the second is purple?
2/13
A bag contains 2 purple marbles and 6 green marbles - Two marbles are drawn at random - so What is the probability that the first marble drawn is green and the second one is purple?
There are 8 marbles in the bag, and 6 are green, so the chance that the first one you pick is green is 6/8 or .75. Let's call the event where you pick the green marble first, G, for green of course. Now since you picked a marble there are only 7 left. If you picked a green one then the chances of picking a purple one are now 2/7 since there are two purple marbles and seven total marbles. Let's call the event of picking the purple marble F, (I was going to use P but we need that letter for probability. Purple is a fine color so I picked F.) Now we use the conditional probability rule that tells us what is the chance of picking purple given that we already picked green. The symbol P(F|G) means probability of event F given that event G has already happened. P(F|G)= (the probability of picking green and purple)/ (probability of picking green.) We know these from above. G=6/8 and If we pick a green, probability of picking a purple is 2/7 so we multiply these to get probability of picking both and we have 6/8x2/7 or 12/56. So 12/56=(Probability of Picking green and purple)/( probability of picking green). We have 12/56=[P(G and F)]/(6/8) we want P(G and F) so we multiply 12/56x 6/8 and we have 72/448 So the answer is : 72/448 or about .16 (NOTE: this would be a totally different problem if we took out the first marble then put it back. It is important to be sure what is being asked. If you replaced the marble, the problem is much easier. It is simply 6/8 x 2/8 =12/64 or 3/16) Some people have trouble remembering or understanding the conditional probability rule. I will take just a second to explain it in the hopes it will make it easier to use and remember. The multiplication rule says if we have two mutually exclusive events, A and B, the probability of A and B is P(A)xP(B), so if we want event A to occur THEN event B, we have P(A)xP(B|A) which means probability of A multiplied by probability of B given A has already happened. This equal probability of A and B so we have: P(A)xP(B|A)=P(A and B) . Now divide by P(A) and we have: P(B|A)=P(A and B)/P(A). This is the way the rule is usually stated. Note: P(A|B)=P(A and B)/P(B).
A bag contains 11 blue marbles 10 purple marbles 17 red marbles 15 green marbles and 3 yellow marbles What is the probability of pulling out a blue or a red marble?
There are 11+10+17+15+3=56 marbles in total. Of those marbles, 11 are blue and 17 are red, so there are 11+17=28 blue and red marbles. Therefore the probability of choosing a blue or red marble is 28/56=.5, or 50%.
Can a Pie graph represent a probability?
Depends on the data, but normally it can. Suppose you have a bag of marbles. There are 100. 5 are purple, 20 are blue, 25 are green, and 50 are red. That means when you make a pie chart 5% will be purple, 20% blue, 25% green, and 50% red. So you can tell from the chart the probility of picking out any color if you take one random marble from the bag. This is an example but the principle is true to many other things.
There were 6 purple socks and 4 orange socks in a drawer Zucky picked one sock without looking and then another without looking replacing the first what is the probability that he picked 2 purple?
Probability of picking purple sock first time is 6/10 or 3/5, second time, probability is 5/9. Thus 3/5 * 5/9 = 15/45 which cancels to 1/3
A bag has 7 blue marbles and 8 purple marbles.What is the probability of picking a blue marble then a purple marble without replacing?
7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability
A jar contains 22 yellow marbles 26 green marbles 17 red marbles and 20 purple marbles A marble is drawn at random what is the probability of not pulling out a purple marble?
probability of pulling out a purple marble = 20/85probability of NOT pulling out a purple marble = 1 - 20/85 = 65/85 = 13/17
If A bag contains 3 red marbles and 5 purple marbles One marble is drawn at random and not replaced Then a second marble is drawn at random What is the probability that the first marble is purple and?
3/5
A bag contains 6 purple marbles and 7 white marbles Two marbles are drawn at random One marble is drawn and not replaced Then a second marble is drawn What is the probability that the first marble?
There are 13 marbles in total. The order is specified.P(1st is white and the 2ndis purple) = (7/13)(6/12) = (7/13)(1/2) = 7/26.
A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
A bag contains 6 purple and 7 white marbles two marbles are drawn at random one marble is drawn and not replaced what is the probability that the fist marble is white and the second is purple?
2/13
There are 10 marbles in a bag 5 are blue 2 are yellow and 3 are purple what is the probability of picking a purple marble?
well blue would b picked 65percent of the time an purple would be 25 and ten percent would be yellow
A box contains 3 red marbles 6 blue marbles 12 green marbles and 4 purple marbles if a marble is drawn from the box what is the probability that it is red?
There are a total of 25 Marbles The chances are 3 out of 25 drawing a Red marble. 3/25 = 12% chance of drawing a red marble
A bag contains 2 purple marbles and 6 green marbles - Two marbles are drawn at random - so What is the probability that the first marble drawn is green and the second one is purple?
There are 8 marbles in the bag, and 6 are green, so the chance that the first one you pick is green is 6/8 or .75. Let's call the event where you pick the green marble first, G, for green of course. Now since you picked a marble there are only 7 left. If you picked a green one then the chances of picking a purple one are now 2/7 since there are two purple marbles and seven total marbles. Let's call the event of picking the purple marble F, (I was going to use P but we need that letter for probability. Purple is a fine color so I picked F.) Now we use the conditional probability rule that tells us what is the chance of picking purple given that we already picked green. The symbol P(F|G) means probability of event F given that event G has already happened. P(F|G)= (the probability of picking green and purple)/ (probability of picking green.) We know these from above. G=6/8 and If we pick a green, probability of picking a purple is 2/7 so we multiply these to get probability of picking both and we have 6/8x2/7 or 12/56. So 12/56=(Probability of Picking green and purple)/( probability of picking green). We have 12/56=[P(G and F)]/(6/8) we want P(G and F) so we multiply 12/56x 6/8 and we have 72/448 So the answer is : 72/448 or about .16 (NOTE: this would be a totally different problem if we took out the first marble then put it back. It is important to be sure what is being asked. If you replaced the marble, the problem is much easier. It is simply 6/8 x 2/8 =12/64 or 3/16) Some people have trouble remembering or understanding the conditional probability rule. I will take just a second to explain it in the hopes it will make it easier to use and remember. The multiplication rule says if we have two mutually exclusive events, A and B, the probability of A and B is P(A)xP(B), so if we want event A to occur THEN event B, we have P(A)xP(B|A) which means probability of A multiplied by probability of B given A has already happened. This equal probability of A and B so we have: P(A)xP(B|A)=P(A and B) . Now divide by P(A) and we have: P(B|A)=P(A and B)/P(A). This is the way the rule is usually stated. Note: P(A|B)=P(A and B)/P(B).
A bag contains 11 blue marbles 10 purple marbles 17 red marbles 15 green marbles and 3 yellow marbles What is the probability of pulling out a blue or a red marble?
There are 11+10+17+15+3=56 marbles in total. Of those marbles, 11 are blue and 17 are red, so there are 11+17=28 blue and red marbles. Therefore the probability of choosing a blue or red marble is 28/56=.5, or 50%.
In a bag containing 6 purple marbles 19 green marbles 5 blue marbles 19 yellow marbles and 17 red marbles what is the probability of pulling out a yellow marble?
Total number of marbles in the bag = 6 + 19 + 5 + 19 + 17 = 66Number of yellow ones = 19If drawing perfectly randomly, then the probability of pulling a yellow one = 19/66 = 28.8% (rounded)
What does varieties?
Variety means the state of being different. For example, if you have a blue marble, a black marble, a white marble, a purple marble, a red marble, and green marble, you would say you have a variety of marbles.
