EVERY three consecutive numbers add to a multiple of 3:
Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1)
This means that for any three consecutive numbers, the total is 3 times the middle number.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
The answer to that question is 49,50,51
This is no set of three consecutive numbers that when multiplied equal 387.
71,72,73 :)
The smallest consecutive three numbers that total 120 are... 39, 40 & 41.
If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
There are no such whole numbers. The sum of three consecutive whole numbers must be a multiple of 3; as 68 is not a multiple of 3 (68 = 3 × 22 2/3) it cannot be the sum of three whole numbers.
For this to be possible with whole numbers, 175 has to be a multiple of three. It's not, it isn't.
A multiple of 3 Also a multiple of 6.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
There are no three consecutive numbers with a sum of 170.
The answer to that question is 49,50,51
79
There are no sets of three consecutive numbers totaling 118.
19, 20, 21
Can't be done. The number has to be a multiple of 3.