3
the total combinations is 36 and the ways of getting 3 is 2 (rolling a 2 and a 1 or a 1 and a 2). Therefore number of ways of not getting 3 is 34. Probability (Not 3) = 34/36 = 17/18
1/9
The probability is 1, if the dice are rolled often enough.
21/36 or 7/12 or 58.33...%
1/6 because the other numbers don't affect the probability
The first dice can show any of the eight numbers. If the dice are to show different numbers the second dice has 7 different numbers out of a possible 8 to chose from. So the probability is 7/8 or 0.875 or 87.5% chance.
It's1/12
1/9
The probability is 1, if the dice are rolled often enough.
If they are normal dice, the probability is 0.
21/36 or 7/12 or 58.33...%
1/6 because the other numbers don't affect the probability
The first dice can show any of the eight numbers. If the dice are to show different numbers the second dice has 7 different numbers out of a possible 8 to chose from. So the probability is 7/8 or 0.875 or 87.5% chance.
Prob(Sum = 5) = 1/9
The probability is 1, if the dice are rolled often enough.
If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36
3
If the dice are fair then it is 5/36.