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Let the consecutive numbers be n and n+1, then
n (n + 1) = 992 : n2 + n = 992 : n2 + n - 992 = 0
This equation factors : (n + 32)(n - 31) = 0
The only positive integer solution is when n - 31 = 0, then n = 31 so n + 1 = 32
The two consecutive numbers are 31 and 32.
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