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Two negative consecutive odd integers that have a product of 63 are -7 and -9.

-7 is larger than -9.

-7 is the answer.

Q: Two negative consecutive odd integers have a product of 63 find the larger number?

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-7

-1

They are 6, 8, 10 and 12.

One possible answer is -4 and -3.

The two numbers are 9 and 11, or indeed -9 and -11. Therefore, the larger number is 11 (or -9).

Related questions

-7

-1

You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210

They are 6, 8, 10 and 12.

One possible answer is -4 and -3.

4,6,8,10

There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.

the sum of two consecutive integers is -241, what is the larger integer?

Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.

The two numbers are 9 and 11, or indeed -9 and -11. Therefore, the larger number is 11 (or -9).

There are no such integers.

The larger is 114, and the other is 112.