Wiki User
∙ 13y agoTwo negative consecutive odd integers that have a product of 63 are -7 and -9.
-7 is larger than -9.
-7 is the answer.
Wiki User
∙ 13y ago-7
-1
They are 6, 8, 10 and 12.
One possible answer is -4 and -3.
The two numbers are 9 and 11, or indeed -9 and -11. Therefore, the larger number is 11 (or -9).
-7
-1
You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210
They are 6, 8, 10 and 12.
One possible answer is -4 and -3.
4,6,8,10
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
the sum of two consecutive integers is -241, what is the larger integer?
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.
The two numbers are 9 and 11, or indeed -9 and -11. Therefore, the larger number is 11 (or -9).
There are no such integers.
The larger is 114, and the other is 112.