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5+5 = 10 (Sum is ten)5*5 = 25 (Product is 25)*this product is maximum for all any 2 real numbers that == 10

two real numbers, whose sum is 8 and product is max, are 4,4. 4+4=8 and 4*4=16.

19

There are no real numbers that satisfy the requirements. The complex solutions are: 1 +/- sqrt(21)

No pair of real numbers can do that.The numbers are4.5 + j 18.43234.5 - j 18.4323

The problem is complete. There is enough information there for it to be solved.

There are no two real numbers that can do that.The numbers that can are (2.5 + i42.343) and (2.5 - i42.353).The symbol ' i ' means the square root of -1.

The question is equivalent to asking if there are two numbers whose sum is 6 (the coefficient of x) and whose product is 18 (the constant term). Since there are no such real numbers, the answer is NO. There is a solution in the complex domain but the normal context for such questions is the real numbers.

1 + sqrt(2) and 3 - sqrt(2) Their sum is 4 Thier product is 1 + 2*sqrt(2)

The product of nine negative real numbers is a negative real number.

It is a Term.

anything Any real number can be expressed or closely approximated as a fraction, the there are an infinite number of pairs of numbers whose product is 20.

Infinitely many. The normal distribution is applicable to a continuous variable whose domain is the whole of the real numbers. Infinitely many. The normal distribution is applicable to a continuous variable whose domain is the whole of the real numbers. Infinitely many. The normal distribution is applicable to a continuous variable whose domain is the whole of the real numbers. Infinitely many. The normal distribution is applicable to a continuous variable whose domain is the whole of the real numbers.

Because it is a product of real numbers. And the set of real numbers is closed under multiplication.

No, the product of two negative numbers is always a positive.

No, they cannot with real numbers. With complex numbers it is possible.

Whenever you multiply two negative real numbers.

Yes.

It is a monomial.

Yes it is.

The grouping in which the numbers are taken does not affect the sum or product.

There are no real numbers with the sum of 4 and a product of -477. The factors of -477 are (1,-477), (3, -159) and (9, -53). The negatives can be switched to the other numbers in those pairs of factors.

Lets see............ (a+ib)(a-ib) = a^2+iab-iab+b^2 = a^2 + b^2 a and b can be any values and a^2+b^2 will be real.

The following rules apply to all real numbers.if either number is zero, then the product is zero.if the signs of two numbers are the same, their product is positive; if the signs are different then the product is negative.for the product of three or more numbers, the associative property can be used to find the product two-at-a-time.

When two negative real numbers are multiplied together, the product is a positive real number.