10 1/2
Look for corresponding parts of the two figures. Their ratio is the scale factor. For example, if you have two similar triangles, one has a side of length 3, and the corresponding side on the other triangle is 5, then the scale factor is 5/3 going from the small triangle to the big, or 3/5 going from the big triangle to the small.
It is 5.6
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the answer to this question is 1:4 10: ? =10x4/1 =40
If at least one vertex of the inner triangle lies on the side of the outer triangle then yes, it is a complex polygon. However, if none of the vertices of the inner triangle are on the sides of the outer triangle then there are two disjoint triangles and that does not represent a polygon.
The three requirements to be similar figures are: Corresponding angles must be congruent (equal in measure). Corresponding sides are in proportion; this means that the ratio of corresponding side lengths is the same for all sides. The figures have the same shape, but can be of different sizes.
Look for corresponding parts of the two figures. Their ratio is the scale factor. For example, if you have two similar triangles, one has a side of length 3, and the corresponding side on the other triangle is 5, then the scale factor is 5/3 going from the small triangle to the big, or 3/5 going from the big triangle to the small.
Having sex
They have the same properties but are smaller in size.
To find the scale factor of two triangles, look first for one pair of corresponding sides--one side from the smaller triangle and the corresponding side from the larger triangle. Divide the larger side length by the smaller side length, and that quotient is your scale factor.
YesFor two triangles to be congruent, their corresponding sides must be of equal length. But for triangles to be similar, they must only have equal angles. For there to be a SAS postulate for similarity, the two corresponding sides would have to be proportionate, not equal. If they were equal, the triangles would be congruent.So, an SAS postulate for similar triangles would mean that two of the sides of the smaller triangle are, for example, half the two corresponding sides of the other triangle. If also the corresponding included angles are equal, then the two triangles would be similar triangles.APEX: similar
Let the perimeter of the triangle MNO be x.Since the perimeters of similar polygons have the same ratio as any two corresponding sides, we have13/26 = 44/x (cross multiply)13x =1,144 (divide both sides by 13)x = 88Or since 13/26 = 1/2, the perimeter of the triangle MNO is twice the perimeter of the triangle HIJ, which is 88.
This is known as the Sierpinski triangle.
It's called a Sierpinski triangle.
When the shape is the same but the form is bigger or smaller
shapes where corresponding angles are the same and corresponding sides are in proportion. they are the same shape and one is either bigger or smaller than the other.
Sierpinski Gasket