By using the 3 digits of a number we can form 3 different two digit numbers.
3C2 = 3!/[(3 - 2)!2!] = 3!/(1!2!) = (3 x 2!)/2! = 3
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
then there would only be a 1. and there would be no 2,3,4,5,6,7,8,9 digit numbers onlya one digit number. and there would be only 1,2,3,4,5,6,7,8,9,numbers to use not 10, 20,30,40 ,50 ,60,70,80,90,100 because they need zeros
In the decimal number system, the highest valued digit is 9. The highest digit that ever appears in any one 'place' of a number is one less than the 'base' of the number. The numbers that everyone is most familiar with ... the numbers you see around you every day ... are numbers written in the 'decimal' system, using the 'base' of 10. So the highest digit in any one place is 9. 'Binary' numbers ... the form most used to represent numbers inside digital circuits and computers ... are constructed in base 2. So the highest digit in any one place is 1, and each of these numbers is just a string of 1's and zeros. Digits can be even higher than 9 in number systems that use other bases. For example, the hexadecimal system (often used in computer science to represent binary numbers) is base 16, so in that case the highest valued digit is "F" which has a value equivalent to 15 in a decimal representation. As an example, the number "FA" hexadecimal, has decimal value 15*16 + 10 = 250.
6
367 ,376 ,396, 369, 379, 397, 637 ,673 ,693, 639, 697, 679 ,763, 736, 769, 796, 793, 739, 976, 967 ,937 ,973, 976, 967 so its twenty-four unless you can use the numbers more than once in each three digit number.
You can use C++ program to decrypt 3 digit number
123, three number 45, two number
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
I think you r cheating Mr.Cheater
24 = 16
You write out the numbers. If you just simply put the digit on the paper it will be incorrect.
You best use scientific notation for such large numbers.
how do you write 4 digit numbers with a 0 in ten and hundred place then use the same number to tell which number is larger
Assuming a seven digit whole number: 1,111,111. But if you have to use at least one (2) digit, then 1,111,112.
Assuming a seven digit whole number: 1,111,111. But if you have to use at least one (2) digit, then 1,111,112.
There is no single word that means what you are looking for.
Dial 1 before the area code and 7-digit number.