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From first equation, -y = 3x + 3.

Substitute in second equation: -3x + 5(3x + 3) = -21

ie 12x = -36 so x = -3 and y = -(-9 + 3) = 6.

Easier method: subtract first equation from second giving -4y = -24 so y = 6, this in first equation gives -6 = 3x + 3, ie 3x = -9 so x = -3

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Q: Use the substitution method to solve the following system of linear equations -3x-y equals 3 -3x-5y equals -21?
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