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2. This would be as a result of rolling a 1 on each of them.

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Q: Using 2 dice what is the most least number to roll?
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Using 3 dice what is the most common number to roll?

The most common number would be 10 and 11. When using 3 dice, the total sum of eyes must be between 3 and 18. The most probably number being rolled can be found simply by calculating the average of the highest and lowest possibilities. (3+18)/2 = 10,5 ; meaning 10 and 11 are the two most probable numbers to be rolled using 3 dice.


What is the most likely number to roll using a dice?

they are all equally likely, just like flipping a coin.


What number shows up most often when you roll 10 dice?

#7


How many die used in craps?

Regular craps is played with 2 dice, but most casinos keep 5 dice on the table and the 3 the shooter isn't using are kept in a bowl.


Using 2 dice what is the most likely number to roll?

AnswerThe most likely number is seven.This can be 1+6, 2+5, 3+4, 4+3, 5+2, 6+1.Remember that dice have no memory - if you have rolled 7 three times in a row the odds of rolling another 7 does not change.this is all wrong don't listen that


Where did the phrase 'the whole box and dice ' originate?

The phrase 'the whole box and dice' originated from dice games such as liar's dice. It is most common in Australian English, and means the whole thing.


Have two dice from numbers 1 - 20 what is the most likely to be rolled?

-19


Why does a 10 sided dice have 9 for the highest number?

Ten-sided dice are often used in games that require a "percentage roll", such as Dungeons & Dragons. Players roll two 10-sided dice, and the numbers rolled are used as digits to form a number between 0 and 99. Using a "0" instead of "10" simplifies this process. For most other games and instances, zeroes on ten-sided dice represent tens. Just FYI - some ten-sided dice do actually have a "10" instead of a "0", but they're fairly rare. I got 4 of them in a board game called Filthy Rich, which - ironically enough - uses numerous references to rolling zeroes instead of tens. Go figure.


Why would you expect the numbers 1 to 6 in a dice to appear the most often?

because most dice only have numbers 1 to 6 on them


What sum are you least likely to get rolling two dice?

all numbers on a die have the same probability to land so any number between 2 and 12 are just as likely as any other number between 2 and 12, just as any other die hase the same probability 2 d20, 2-40 any to are just as likely as the rest. so 0 is the least likely number. Well, yes, since 0 is impossible to be the sum of 2 dice, it is least likely. So is any other number less than 2 or greater than 12, or a number that is not a whole number. But of those that actually can come up as the sum of 2 dice, 7 is the most likely because there are 6 ways to get it (1 and 6, 2 and 5, 3 and 4, 4 and 3, etc.). The least likely sums are 2 and 12, because each can only occur 1 way (a pair of 1's or a pair of 6's). These are referred 2 by gamblers as snake eyes and box cars.


What is the most likely outcome when tossing two dice?

Seven - there are more ways to make seven than there are to make any other number.


What are the Odds of rolling doubles?

Answer 1:The odds are very easy to calculate. Simply divide the number of "valid" rolls against all possible rolls. For ease, you can write down all possible combination for the 2 dice.1-1; 1-2; 1-3; 1-4....and so on, remember 1-4 and 4-1 are different rollsThere are 36 unique possible combination, and 6 of them are doubles, so that's 6/36 chances (and since 6 goes into 36, 6 times, this reduces to 1/6) or about 17%Answer 2:Another way to look at this problem, generically, is to assume we have an 'n' face dice. In most cases, dice have 6 faces (1, 2, 3, 4, 5, 6). But why not create a solution that works for any number of sides? Well, if we are trying to calculate the probability of rolling two dice (dice-1 and dice-2) of 'n' sides at the same time and having them turn up as doubles, only one of the dice really matters. Here's why. Dice-1 is guaranteed to land on a number 1-n. This will happen every time (on a fair dice, disregarding freak incidents). What we are trying to calculate is the probability that dice-2 will land on the SAME number as dice-1. Dice-2 can only land on one of 'n' values: 1, 2, 3, 4, 5, 6, ... , 'n'. For you non math folks, this just means it must land on a number from 1 to 'n' where 'n' is the number of sides on your dice. Out of all of the sides that dice-2 can PHYSICALLY land on, one of the sides MUST necessarily have the same as the value that dice-1 landed on. That is to say, if dice-1 landed on the value 3, there must be some chance that dice-2 will also land on the value 3. The probability of this occurring on a fair die is 1 divided by the total number of possible outcomes, which would be 'n'. So, really, there is a 1/n chance that dice-2 will land on the same number as dice-1. Thus, our probability for rolling doubles is simple 1/n. For our 6 sided dice example, our dice-1 lands on some value between 1 and 6 and there is a 1/6 chance dice-2 will match it.