really easy question
a=6 , b=8 , c= 10
For the right angle triangle to comply with Pythagoras' theorem then c, which will be the hypotenuse, must be 10 units in length. Pythagoras' theorem: 82+62 = 100 and the square root of this is 10 which is the length of the hypotenuse.
Using Pythagoras theorem: 6^2 + 8^2 = 100 and its square root is 10 which is the length of the hypotenuse
X= (3/5 , -2)
Equation: 6x^2 +2x +k = 0 Using the discriminant formula: k = 1/6 Using the quadratic equation formula: x = -1/6 Check: 6(-1/6)^2 +2(-1/6) +1/6 = 0
Using Pythagoras' theorem the hypotenuse is 10 cm
Using Pythagoras' theorem for a right angle triangle if the legs are 6 and 8 then the hypotenuse works out as 10
By using Pythagoras it is: 6+8+6+8 = 28 inches
Using Pythagoras' theorem its width is 6 units in length.
That factors to 2(x + 4)(x + 6) x = -4, -6
Consider the line segment between the points of (6, 8) and (3, 4) Using Pythagoras' theorem its length is: (6-3)squared+(8-4)squared = 25 So the square root of 25 is 5 which is the length of the line
Using Pythagoras' theorem it is about 10.81665383 inches.
quad formula: {6 +/- sqrt[62 - 4*1*(-16)]}/2 = {6 +/- sqrt(36+64)}/2 = {6 +/- sqrt(100)}/2 = {6 +/- 10}/2 = -4/2 or 16/2 = -2 or 8