0
1 = 4*4/(4*4)
2 = 4/4+4/4
3 = (4+4+4)/4
4 = (4-4)/4+4
5 = 4^(4-4)+4
6 = (4+4)/4+4
7 = 4+4-4/4
8 = 4+4+4-4
9 = 4/4+4+4
10 = (4*4+4!)/4
11 = (4+4!)/4+4
12 = (4-4/4)*4
13 = (4+4!+4!)/4
14 = 4!/4+4+4
15 = 4*4-4/4
16 = 4*4+4-4
17 = 4*4+4/4
18 = (4*4!-4!)/4
19 = 4!-(4+4/4)
20 = (4/4+4)*4
21 = 4!+4/4-4
22 = 4!-(4+4)/4
23 = 4!-4^(4-4)
24 = 4*4+4+4
25 = 4!+(4/4)^4
26 = 4!+4!/4-4
27 = 4!+4-4/4
28 = (4+4)*4-4
29 = 4/4+4!+4
30 = (4*4!+4!)/4
31 = (4+4!)/4+4!
32 = 4^4/(4+4)
33 = (4-.4)/.4+4!
34 = 4!/4+4+4!
35 = (4.4/.4)+4!
36 = (4+4)*4+4
37 = 4/.4+4+4!
38 = 44-4!/4
39 = (4*4-.4)/.4
40 = (4^4/4)-4!
41 = (4*4+.4)/.4
42 = 4!+4!-4!/4
43 = 44-4/4
44 = 4*4+4+4!
45 = (4!/4)!/(4*4)
46 = (4!-4)/.4 - 4
47 = 4!+4!-4/4
48 = (4*4-4)*4
49 = 4!+4!+4/4
50 = (4*4+4)/.4
51 = 4!/.4-4/.4
52 = 44+4+4
53 = 44+4/.4
54 = (4!/4)^4/4!
55 = (4!-.4)/.4-4
56 = 4!+4!+4+4
57 = 4/.4+4!+4!
58 = (4^4-4!)/4
59 = 4!/.4-4/4
60 = 4*4*4-4
61 = 4!/.4+4/4
62 = (4!+.4+.4)/.4
63 = (4^4-4)/4
64 = 4^(4-4/4)
65 = 4^4+4/4
66 = (4+4!)/.4-4
67 = (4+4!)/.4+4
68 = 4*4*4+4
69 = (4+4!-.4)/.4
70 = (4^4+4!)/4
71 = (4!+4.4)/.4
72 = (4-4/4)*4!
73 = (.4√4+.4)/.4
74 = (4+4!)/.4+4
75 = (4!/4+4!)/.4
76 = (4!-4)*4-4
77 = (4!-.4)/.4+4!
78 = (4!*.4+4!)/.4
79 = (.4√4-.4)/.4
80 = (4*4+4)*4
81 = (4/4-4)^4
82 = 4!/.4+4!+4
83 = (4!-.4)/.4+4!
84 = (4!-4)*4+4
85 = (4/.4+4!)/.4
86 = (4-.4)*4!-.4
87 = 4!*4-4/.4
88 = 4^4/4+4!
89
90 = (4!/4)!/(4+4)
91
92 = (4!-4/4)*4
93
94 = (4+4!)/.4 + 4!
95 = 4!*4-4/4
96 = 4!*4+4-4
97 = 4!*4+4/4
98 = (4!+.4)*4+.4
99 = (4!+4!-4)/.4
100 = 4*4/(.4*.4)
Wiki User
∙ 11y ago
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When four times the number is added to 7 times the result is 33?
4 times a number added to 7 times the number equals 33
How would you write five less than four times a number as an algebra expression?
4n-5 (Which is four times a number minus 5)
How do you work out numbers squared?
A number squared is just that number times itself. For example four squared is four times four equals sixteen (42 = 4 x 4 = 16).
What is twice a number is equal to five more than four times the number?
3
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5*4+3+2
What is a four digit number divisible by eleven?
1100
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3*3 - 3/3
How do you make 31 using only the number 4?
As a solution to the four fours problem (using the number four no more than four times to come up with the solution, 31 is equal to (4!+4)/4+4!
How do you get the answer 9 using 2 four times?
By dividing it until you stop with a number that can be divided by two using the .0's
How do you make 7 using the number 4 four times?
You divide 7 by 4 which is 1.75.
How can you get the answer 27 from using the number 3 four times?
3³ ÷ 3 x 3 = 27
How do you get the answer 43 only using the number 4 four times?
How about: 44-(4/4) = 43
How do you make the number 10 using 3 four times?
3*3 + 3/3 = 10
Which is the largest 4 digits number using 4 at 4 times?
It looks like you're asking what is the largest 4-digit number which has four 4's for digits - with a four digit number using four 4's, there is only one such number: 4444. Maybe I'm not understanding the wording of your question.
Using the number 4 four times can you make 1-20?
((4/4) + 1) * 4=20
With only using the numbers one four six and four each once using any operation add subtract divide or times. How would i get the number 25?
4*6+1
What is four times a number and four?
16
