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Q: How do you write 450 as the product of its prime factors in index form?

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As a product of its prime factors: 23*3*5 = 120

15 = 31*51

48 = 24 x 3

As a product of its prime factors: 3*7 = 21

write the number 14as a product of prime factor?

As a product of its prime factors: 2*3*3*3*5 = 270

56 = 2 x 2 x 2 x 7 = 23 x 7

As a product of its prime factors: 2*5*17 = 170

As a product of its prime factors: 3*5*7*11 = 1155

As a product of its prime factors: 2*2*3*7 = 84

As a product of its prime factors: 5*5*5*11 = 1375

As a product of its prime factors: 3*5*7*7 = 735

As a product of its prime factors: 2*5*5*5 = 250

23 x 3 x 5 = 120

It is: 2^3 times 3^1 times 5^2 = 600

As a product of its prime factors: 2*2*5*5*17 = 1700

123 written as a product of prime factors is: 123 = 3 X 41.

1000 as a product of its prime factors is written as: 2 x 5 = 10

As a product of its prime factors: 2*2*2*3*5*5*5 = 3000

As a product of its prime factors: 3*3*3*11 = 297

As a product of its prime factors: 2*2*19 = 76

As a product of its prime factors in exponent form: 3^6 = 729

write the prime factorization of the number. simple as that.

2x2x13

You can't. 59 is already prime.

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