Let, n=10
2n+1=?
2(10)+1= 21
Let, n=10
2n+1=?
2(10)+1= 21
1st term= 3 2nd term = 5 Nth term = 2n+1 10th term= 21 = 2(10)+1
The nth term of the sequence is 2n + 1.
Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.
2n(n+1)
5
is 219 in the sequence of 4n-3
n = 1, 2n = 2 n = 2, 2n = 4 n = 3, 2n = 6 2, 4, 6, ..., 2n where n = 1, 2, 3, ... This is an arithmetic sequence, where the first term is 2 and the common difference is 2.
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
2n(n+1)
(1/2n-r)2+((n2+2n)/4) where n is the row number and r is the position of the term in the sequence
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)
2n-1 to the tenth term = 1