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Q: What is the sum of the first 14 term of the sequence 1,5,9,13?

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nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.

That's the famous Fibonacci sequence, where every term is the sum of the previous two.

16

The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.

sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10

The sum of an arithmetical sequence whose nth term is U(n) = a + (n-1)*d is S(n) = 1/2*n*[2a + (n-1)d] or 1/2*n(a + l) where l is the last term in the sequence.

The geometric sequence with three terms with a sum of nine and the sum to infinity of 8 is -9,-18, and 36. The first term is -9 and the common ratio is -2.

875

A binary sequence is a sequence of [pseudo-]randomly generated binary digits. There is no definitive sum because the numbers are random. The sum could range from 0 to 64 with a mean sum of 32.

Given an arithmetic sequence whose first term is a, last term is l and common difference is d is:The series of partial sums, Sn, is given bySn = 1/2*n*(a + l) = 1/2*n*[2a + (n-1)*d]

The 1st term is (X). The 2nd term is (4X-5). The 3rd term is (16X-25). The average of the 2nd and 3rd terms is 1/2 of their sum. Their sum is (4X-5) + (16X-25) = (20X-30). Their average is (10X-15).

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