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Q: What 2 factors have a product of 40 and a sum of 13?

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8 and 5

As a product of its prime factors: 2*2*2*5 = 40 As a product of its prime factors: 2*2*2*7 = 56 As a product of its prime factors: 3*13 = 39

8 and 5

The anwer is 8 and 5 and thedifference of the two is 3

When the product of 15 and 40 is divided by the sum of 15 and 45, what is the quotient?

40

2,4,8,10 and 16 are factors of 400.

20+20=40 20x20=400

The product of all of the factors of 40 is (1, 2, 4, 5, 8, 10, 20, 40) : 2,560,000

368

5(8 + 5)

24 and 16 are factors of 48

2,560,000

1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75

5(8 + 5) = (5 x 8) + (5 x 5) = 5 x 13 = 65

8 and -5

-37

1 + 3 + 9 + 27 = 40

The product of the prime factors of any positive integer is equal to the integer itself.

If the product of the two numbers is the sum times 24, then the product of the two numbers is 2400. 40 times 60 is 2400, and 40 plus 60 is 100. The two numbers are 40 and 60.

5(8 + 5)

20 and 20.

34

37

40: 1 + 40 + 2 + 20 + 4 + 10 + 5 + 8 = 90