1x68
2x34
4x17
____
68x1
34x2
17x4
How about: 2*2*17 = 68 as a product of its prime factors
1, 68 2, 34 4, 17 8, 8.5 etc.
2 x 34 4 x 17
I don't understand your question but I can assume you're using whole numbers less than 68 and greater than 1 to find multiplicand pairs that equal 68. Given that, 68 breaks down into the integers 2, 2, and 17 (multiplied together they equal 68). So anyone combination of these three numbers will give you your axb=68 equations. So in this example you can have 2x34 or 4x17 besides the obvious 1*68
2 and 53
1 2
Two numbers that equal 136 are 136/1 and 0.007352941.
143 and 2
4400 and 2
The numbers are -10 and -70
1 and 83
1 and 2