2,4
3
If we insist on the condition that all the numbers must be integers... The only way this can happen is if the quotient and one of the other numbers are negative. For example, if the original numbers are -4 and 2, then their sum is -2, and the quotient of -4 divided by 2 is also -2. I believe that's the only integer example of a set of numbers satisfying that criterion.
The "quotient" of two numbers is the result of a multiplication sum. Therefore, if 6x = -12, then x = -2.
14 + 2 = 16 14/2 = 7 The two numbers are therefore 14 and 2.
The numbers are -2, -1, 0, 1 and 2.
the quotient of 2 numbers is 8. The sum of the 2 numbersis 72. What are the 2 numbers
2 and 3. 2 + 6 = 8, the sum. 6 / 2 = 3, the quotient.
3
If we insist on the condition that all the numbers must be integers... The only way this can happen is if the quotient and one of the other numbers are negative. For example, if the original numbers are -4 and 2, then their sum is -2, and the quotient of -4 divided by 2 is also -2. I believe that's the only integer example of a set of numbers satisfying that criterion.
The numbers are: 80 and 4
-- Add the two numbers. -- Divide their sum by 2 . -- The quotient is the mean of the two numbers.
The "quotient" of two numbers is the result of a multiplication sum. Therefore, if 6x = -12, then x = -2.
The quotient of 2 and the sum of 30 and -4 is negative thirteen.
14 + 2 = 16 14/2 = 7 The two numbers are therefore 14 and 2.
A single number cannot have a sum, or a quotient.
60
The numbers are -2, -1, 0, 1 and 2.